<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: A Twelve Cent Binary Calendar</title>
	<atom:link href="http://www.exploringbinary.com/a-twelve-cent-binary-calendar/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.exploringbinary.com/a-twelve-cent-binary-calendar/</link>
	<description>Binary Numbers, Binary Code, and Binary Logic</description>
	<lastBuildDate>Mon, 30 Jan 2012 01:37:52 +0000</lastBuildDate>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	<generator>http://wordpress.org/?v=3.2.1</generator>
	<item>
		<title>By: Rick Regan</title>
		<link>http://www.exploringbinary.com/a-twelve-cent-binary-calendar/comment-page-1/#comment-120</link>
		<dc:creator>Rick Regan</dc:creator>
		<pubDate>Thu, 19 Feb 2009 23:13:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.exploringbinary.com/?p=203#comment-120</guid>
		<description>Jesse,

  Yes, 2^20 - 1 = 1,048,575 positions.

  I&#039;ve tried counting in binary on one hand but it&#039;s kind of hard to do without getting help from the other hand (to keep the bits either up or down and not ``indeterminate&#039;&#039;). Two hands would be hard. Forget two feet too!

  There&#039;s lots written about binary finger counting. Here&#039;s one video showing counting to 31 on one hand: http://www.youtube.com/watch?v=z8p-tLD5E5A&quot;. It uses ``negative logic&#039;&#039; though -- I prefer finger up = 1, finger down = 0.</description>
		<content:encoded><![CDATA[<p>Jesse,</p>
<p>  Yes, 2^20 &#8211; 1 = 1,048,575 positions.</p>
<p>  I&#8217;ve tried counting in binary on one hand but it&#8217;s kind of hard to do without getting help from the other hand (to keep the bits either up or down and not &#8220;indeterminate&#8221;). Two hands would be hard. Forget two feet too!</p>
<p>  There&#8217;s lots written about binary finger counting. Here&#8217;s one video showing counting to 31 on one hand: <a href="http://www.youtube.com/watch?v=z8p-tLD5E5A" rel="nofollow">http://www.youtube.com/watch?v=z8p-tLD5E5A</a>&#8220;. It uses &#8220;negative logic&#8221; though &#8212; I prefer finger up = 1, finger down = 0.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Jesse Jenkins</title>
		<link>http://www.exploringbinary.com/a-twelve-cent-binary-calendar/comment-page-1/#comment-119</link>
		<dc:creator>Jesse Jenkins</dc:creator>
		<pubDate>Thu, 19 Feb 2009 22:35:15 +0000</pubDate>
		<guid isPermaLink="false">http://www.exploringbinary.com/?p=203#comment-119</guid>
		<description>When I swim, I count both my laps as well as the number of strokes per lap.
I try to do a mile in the neighborhood of 30 minutes, with early 25 meter laps
taking about 7 complete strokes (both arms) and never expanding beyond 9 complete strokes.  It&#039;s important to count strokes and laps, but it gets boring.  To make it more interesting, I&#039;ve also been thinking about how I might go about
counting on my fingers and toes.  If you take each digit and think of it extended as having a &quot;1&quot; present in its position, and curling under to represent a &quot;0&quot;, you have 20 positions, which permits representation up to (2**23)-1,
which lets yo count beyond a million just using your fingers and toes - right?
Hint: use your fingers for the least significant bits as they change the most.</description>
		<content:encoded><![CDATA[<p>When I swim, I count both my laps as well as the number of strokes per lap.<br />
I try to do a mile in the neighborhood of 30 minutes, with early 25 meter laps<br />
taking about 7 complete strokes (both arms) and never expanding beyond 9 complete strokes.  It&#8217;s important to count strokes and laps, but it gets boring.  To make it more interesting, I&#8217;ve also been thinking about how I might go about<br />
counting on my fingers and toes.  If you take each digit and think of it extended as having a &#8220;1&#8243; present in its position, and curling under to represent a &#8220;0&#8243;, you have 20 positions, which permits representation up to (2**23)-1,<br />
which lets yo count beyond a million just using your fingers and toes &#8211; right?<br />
Hint: use your fingers for the least significant bits as they change the most.</p>
]]></content:encoded>
	</item>
</channel>
</rss>

