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Exploring Binary » Background math http://www.exploringbinary.com Binary Numbers, Binary Code, and Binary Logic Tue, 31 Jan 2012 16:38:56 +0000 en hourly 1 http://wordpress.org/?v=3.2.1 The Laws of Exponents http://www.exploringbinary.com/the-laws-of-exponents/ http://www.exploringbinary.com/the-laws-of-exponents/#comments Fri, 14 Nov 2008 19:06:32 +0000 Rick Regan http://www.exploringbinary.com/?p=76 By Rick Regan (Copyright © 2008-2012 Exploring Binary)

The Laws of Exponents

]]> For your reference, here is a summary of the laws of exponents:

$\mbox{\small{\displaystyle {x^0 = 1}}}$
$\mbox{\small{\displaystyle {x^1 = x}}}$
- Special case: $\mbox{\small{\displaystyle {1^{a} = 1}}}$
- Special case: $\mbox{\small{\displaystyle {x^{-1} = \frac{1}{x}}}}$
$\mbox{\small{\displaystyle {\frac{1}{x^{-a}} = x^{a}}}}}$
$\mbox{\small{\displaystyle {{x^a} \cdot {x^b} = x^{a+b}}}}$
$\mbox{\small{\displaystyle {\frac{x^a}{x^b} = x^{a-b}}}}$
$\mbox{\small{\displaystyle {\left({x^a}\right)^{b} = x^{ab}}}}$
$\mbox{\small{\displaystyle {{\left(x \cdot y\right)}^a = x^a \codt y^a}}}$
- Special case: $\mbox{\small{\displaystyle {\left({\frac{1}{y}}\right)^a = \frac{1}{y^a}}}}$
- Special case: $\mbox{\small{\displaystyle {x^{\frac{1}{b}} = \sqrt[b]{x}}}}$

By Rick Regan (Copyright © 2008-2012 Exploring Binary)

The Laws of Exponents

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